Check is a player in the array

Hey Guys!
I try to make a Build Command and i have the question how can i check is the Player in the variable $buildPlayer? Thanks for answers
Bye

 

example how to search:

PHP:

$getArray = []; // idk if you want from a file or wht but i give ya an array
$playerName = $player->getName();
// how to search player name in an array:
// use array_search
if(array_search(strtolower($playerName), strtolower($getArray)) == true){ // i'm using 'if' to find whether the search is true or not
 // code to be execute
}


 

I think you can't use strtolower on array_search, it needs to be string!

 

You can use this.

PHP:

$buildPlayer  = [];
$name = $player->getName();
if(isset($buildPlayer[$name])){
         //found
} else {
         //not found
}

 

http://php.net/manual/en/function.array-search.php

PHP:

mixed array_search ( mixed $needle , array $haystack [, bool $strict = FALSE ] )


 

PHP:

array_map("strtolower", $array);

Or if you want to change the keys to lowercase:

PHP:

array_change_key_case($array, CASE_LOWER);

 

http://php.net/manual/en/function.strtolower.php

Code:

string strtolower ( string $string )

You can't pass array in strtolower!

 

You can't, i have tested on my server and your code gives me an error bout that.

 

PHP:

$buildPlayers = [];
$buildPlayers["example1"] = null;
$buildPlayers["example2"] = null;
/**
 * in $bulidPlayers....
 * Array (
 *   ["example1"] => null,
 *   ["example2"] => null
 * )
 */
$result = array_key_exists("example1", $buildPlayers);
// bool(true)


As SOF3 says, using isset() is faster than the function overhead by array_key_exists(),
but this method is recommended because there are pitfalls like the following.

PHP:

$example = [
  "steve" => null
];
var_dump(array_key_exists("steve", $example));
// output: bool(true)

var_dump(isset($example["steve"]));
// output: bool(false)
// If the value is not null, true will be returned securely.


 

I have a build mode plugin, you can message me if you want it

 

isn't there like an in_array?

PHP:

$array = ["Bob", " Sarah"];
if(in_array("Bob", $array)){
    // Found in the array
}