Solved Dropdown PlayerList

PHP:

private $PlayerList = [];
    /**
     * @param Player $sender
     */
    public function ReportPlayer(Player $sender) {
        $api = $this->plugin->getServer()->getPluginManager()->getPlugin("FormAPI");

        if($api == null || $api->isDisabled()) {
            return true;
        }

        $list = [];
        foreach ($this->plugin->getServer()->getOnlinePlayers() as $p) {
            $list[] = $p->getName();
        }
        $this->PlayerList[$sender->getName()] = $list[]; // 79

        $form = $api->createCustomForm(function(Player $sender, $data) {
            $this->name = $this->playerList[$sender->getName()][$data[0]];
            $this->raison = $data[1];

            // code

            if($this->name instanceof Player) {
               // code
                if($sender->isOp()) {
                    $sender->sendMessagfe("§7[§dREPORT§7] Le joueur a bien été signalé.");
                } else {  
                    $sender->sendMessage("§7[§dREPORT§7] Votre prochain report peut être effectué dans 2 minutes.");
                    $sender->sendMessage("§7[§dREPORT§7] Le joueur a bien été signalé.");
                }
            } else {
                $sender->sendMessage("§7[§dREPORT§7] Le joueur n'a pas été trouvé sur notre serveur.");
            }

        });
        $form->setTitle("§f- §dREPORT §f-");
        $form->addDropdown("Joueur", $this->PlayerList[$sender->getName()]);
        $form->addInput("Raison", "Anti AFK");
        $form->sendToPlayer($sender);
    }

He tells me I can't use [] after PlayerList on line 79

 

Which line is line 79 :3?

 

$this->PlayerList[$sender->getName()] = $list[];

 

Will response next 6 hours (P/s: I have to go to my school)

 

Hi!

PHP:

//this is correct
$this->PlayerList[$sender->getName()] = $list;

//this is incorrect PHP syntax
$this->PlayerList[$sender->getName()] = $list[]; 

 

It's true